PHP命令行怎样获取参数
$argv
(PHP 4, PHP 5, PHP 7)$argv — Array of arguments passed to script
<?php
var_dump($argv);
?>
php script.php arg1 arg2 arg3
//结果
array(4) {
[0]=>
string(10) "script.php"
[1]=>
string(4) "arg1"
[2]=>
string(4) "arg2"
[3]=>
string(4) "arg3"
}